def getBFFs[F[_]: ConcurrentEffect : Par] = List(1, 2, 3).traverse(getBFF[F])
思路：链表转数组 + 单调栈（从后往前遍历）。与「下一个更大元素」模板一致，仅需将链表值先提取到数组。
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“We can confirm we filed a request,” Nintendo of America said in a statement. “We have nothing else to share on this topic.”
。关于这个话题，纸飞机下载提供了深入分析
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are just a little larger than a neat power of two, and virtual memory is。PDF资料是该领域的重要参考